单选题
执⾏下⾯C++代码可以找出千位与个位的和恰好等于中间两位的四位数，横线处应该填⼊（ ）
int count = 0;
int a, bc, d, tmp;
for (int i = 1000; i <= 9999; i++) {
a = (tmp = i) / 1000;
_________________________
bc = tmp / 10;
d = tmp - bc * 10;
if ( a + d == bc) {
count++;
}
}
cout << count;A.
tmp = i / 10;
B.
tmp = i % 100;
C.
tmp -= a * 1000;
D.
tmp = i - i%1000;
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